A voltage of V sin(4t) is applied to a pure capacitor. Which of the following represents the current through the capacitor?

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ISRO (VSSC) Technician Electrician 2019 Official Paper
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  1. A sin \(\left( {4t - \frac{\pi }{4}} \right)\)
  2. A sin \(\left( {4t - \frac{\pi }{2}} \right)\)
  3. A sin \(\left( {4t + \frac{\pi }{2}} \right)\)
  4. A sin \(\left( {4t + \frac{\pi }{4}} \right)\)

Answer (Detailed Solution Below)

Option 3 : A sin \(\left( {4t + \frac{\pi }{2}} \right)\)
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Detailed Solution

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Concept:

  • In a purely resistive circuit, voltage and current are in the same phase i.e. angle between current and voltage is 0°.
  •  In a purely inductive circuit, current lags behind voltage by an angle 90° i.e. angle between current and voltage is - 90°.
  • In a purely capacitive circuit, current leads the voltage by an angle 90° i.e. angle between current and voltage is + 90°.

 

Application:

The voltage applied to a pure capacitor = V sin(4t)

Now current through the pure capacitor is

\(i = A\;sin\left( {4t + \frac{\pi }{2}} \right)\)

Where A is the peak value of current

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