Question
Download Solution PDFA person divides his total route of journey into three equal parts and decides to travel the three parts at the speeds of 80 km/h, 60 km/h and 30 km/h, respectively. What is the average speed during the journey?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A person divides his total route of journey into three equal parts and decides to travel the three parts at the speeds of 80 km/h, 60 km/h and 30 km/h, respectively.
Formula used:
Average Speed = Total Distance / Total Time
Calculation:
Let total distance be 3D (since route is divided into three equal parts, each of distance D)
Time taken for first part = D / 80
Time taken for second part = D / 60
Time taken for third part = D / 30
Total Time = (D / 80) + (D / 60) + (D / 30)
⇒ Total Time = D (1/80 + 1/60 + 1/30)
⇒ Total Time = D (3/240 + 4/240 + 8/240)
⇒ Total Time = D (15/240)
⇒ Total Time = D / 16
Total Distance = 3D
Average Speed = Total Distance / Total Time
⇒ Average Speed = 3D / (D / 16)
⇒ Average Speed = 3D × 16 / D
⇒ Average Speed = 48 km/h
∴ The correct answer is option (3).
Last updated on Jun 26, 2025
-> The Staff selection commission has released the SSC CHSL Notification 2025 on its official website on 23rd June 2025.
-> The SSC CHSL Apply Online 2025 has been started and candidates can apply online on or before 18th July.
-> The SSC has released the SSC CHSL exam calendar for various exams including CHSL 2025 Recruitment. As per the calendar, SSC CHSL Application process will be active from 23rd June 2025 to 18th July 2025.
-> The SSC CHSL is conducted to recruit candidates for various posts such as Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. under the Central Government.
-> The SSC CHSL Selection Process consists of a Computer Based Exam (Tier I & Tier II).
-> To enhance your preparation for the exam, practice important questions from SSC CHSL Previous Year Papers. Also, attempt SSC CHSL Mock Test.
-> The UGC NET Exam Analysis 2025 for the exam conducted on June 25 is out.