Question
Download Solution PDFA parallel plate capacitor made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with an (angular) frequency of 320 rad/s. What is the rms value of conduction current?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The RMS value of conduction current is \(I = \frac{V}{X_c}\)
where \(X_c = \frac{1}{ω C}\)
Therefore, I = VωC
Where ω = Frequency in rad/s, C = Capacitance of the capacitor, V = voltage supplied and Xc = Capacitive reactance
Calculation:
Given: C = 100 pF, V = 230 V, ω = 320 rad/s
⇒ I = 230 × 320 × 100× 10-12 A
⇒ I = 7.36 × 10-6 A
⇒ I = 7.36 μA
Hence the correct option is 7.36 μA.
Last updated on Jun 19, 2025
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