A helical compression spring of stiffness K is cut into two pieces, each having equal number of turns and kept side by side under compression. The equivalent spring stiffness of this new arrangement is equal to:

This question was previously asked in
ESE Mechanical 2015 Paper 2: Official Paper
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  1. 4K
  2. 2K
  3. K
  4. 0.5K

Answer (Detailed Solution Below)

Option 1 : 4K
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ST 1: UPSC ESE (IES) Civil - Building Materials
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When spring is cut into two pieces, its stiffness will be doubled.

05.05.2018.0.15

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