A bullet of mass 'a' and velocity 'b' is fired into a large block of wood of mass 'c'. The bullet gets embedded into the block of wood. The final velocity of the system is

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  1. \(\frac{b}{a+b} \times c\)
  2. \(\frac{a+b}{c} \times a\)
  3. \(\frac{a}{a+c} \times b\)
  4. \(\frac{a+c}{a} \times b\)

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Option 3 : \(\frac{a}{a+c} \times b\)
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Calculation:

Given that a bullet of mass 'a' and velocity 'b' is fired into a large block of wood of mass 'c'. The bullet gets embedded into the block of wood. To find the final velocity of the system, we will use the principle of conservation of momentum.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision, assuming no external forces act on the system.

The initial momentum of the system is:

Momentum before = mass of bullet × velocity of bullet = a × b

The final momentum of the system after the bullet gets embedded in the block is:

Momentum after = (mass of bullet + mass of block) × final velocity = (a + c) × v

By conservation of momentum, we equate the initial momentum to the final momentum:

a × b = (a + c) × v

Solving for the final velocity v:

v = (a × b) / (a + c)

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