Single Efficiency MCQ Quiz in मल्याळम - Objective Question with Answer for Single Efficiency - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 27, 2025
Latest Single Efficiency MCQ Objective Questions
Top Single Efficiency MCQ Objective Questions
Single Efficiency Question 1:
12 men can complete a work in 10 days. How many more men are required to complete the work in 6 days?
Answer (Detailed Solution Below)
Single Efficiency Question 1 Detailed Solution
Given :
12 men can complete a work in 10 days.
Calculation :
Let the efficiency of one man be M.
⇒ 12M × 10 = (12M + xM) × 6
⇒ 120M = 72M + 6xM
⇒ 48M = 6xM
⇒ x = 8
∴ The correct answer is 8.
Alternate MethodLet's denote the total work as W.
⇒ W = 12 men × 10 days
⇒ W = 120 man-days
Now, let M be the number of men required to complete the work in 6 days.
⇒ 120 man-days = M men × 6 days
⇒ M = 120 man-days/6 days = 20 men
Number of more men required = M - 12 men
⇒ 20 men - 12 men = 8 men
Single Efficiency Question 2:
A worker completes \(\frac{3}{5}\) of a work in 12 days. In how many days will he complete \(\frac{3}{4}\) of the work?
Answer (Detailed Solution Below)
Single Efficiency Question 2 Detailed Solution
Concept used:
Total work = Efficiency × Time
Calculation:
Time taken by worker to complete 3/5 part of a work = 12 days
Time taken by worker to complete whole work = 12 × 5/3 = 20 days
Time taken by worker to complete 3/4 part of a work = 15 days
The answer is 15 days.
Single Efficiency Question 3:
14 persons can build a house in 60 days. How long will it take 30 persons to build the same house, provided that they all work at the same rate?
Answer (Detailed Solution Below)
Single Efficiency Question 3 Detailed Solution
Given :
14 persons can build a house in 60 days.
Calculation :
⇒ 14P× 60 = 30P × x
⇒ x = 14P × 60/30P
⇒ x = 14 × 2
⇒ x = 28
∴ The correct answer is 28 days.
Single Efficiency Question 4:
39 persons can repair a road in 12 days , working 5 hours a day . In how many days will 30 persons , working 6 hours a day , complete the work?
Answer (Detailed Solution Below)
Single Efficiency Question 4 Detailed Solution
Given:
39 persons can repair a road in 12 days, working 5 hours a day.
Formula Used:
Work = Number of persons × Number of days × Number of hours per day
Calculation:
Work done by 39 persons in 12 days, working 5 hours a day:
Work = 39 × 12 × 5
Work = 2340
Let the number of days required for 30 persons working 6 hours a day be D.
Work = 30 × D × 6
Since the total work is the same, we equate the two expressions for work:
⇒ 39 × 12 × 5 = 30 × D × 6
⇒ 2340 = 180D
⇒ D = 2340 / 180
⇒ D = 13
∴ The correct answer is option 2.
Single Efficiency Question 5:
39 persons can repair a road in 12 days , working 5 hours a day . In how many days will 30 persons , working 6 hours a day , complete the work?
Answer (Detailed Solution Below)
Single Efficiency Question 5 Detailed Solution
Given:
39 persons can repair a road in 12 days, working 5 hours a day.
Formula Used:
Work = Number of persons × Number of days × Number of hours per day
Calculation:
Work done by 39 persons in 12 days, working 5 hours a day:
Work = 39 × 12 × 5
Work = 2340
Let the number of days required for 30 persons working 6 hours a day be D.
Work = 30 × D × 6
Since the total work is the same, we equate the two expressions for work:
⇒ 39 × 12 × 5 = 30 × D × 6
⇒ 2340 = 180D
⇒ D = 2340 / 180
⇒ D = 13
∴ The correct answer is option 2.
Single Efficiency Question 6:
80 men can construct a small footpath in 60 days. How many more men should be employed if the job is to be finished in 20 days?
Answer (Detailed Solution Below)
Single Efficiency Question 6 Detailed Solution
Given:
80 men can construct a small footpath in 60 days.
We need to find how many more men should be employed if the job is to be finished in 20 days.
Formula Used:
Work = Men × Days
Calculation:
Work done by 80 men in 60 days:
Work = 80 × 60
Work = 4800 man-days
Let x be the number of men required to complete the work in 20 days:
Work = x × 20
Since the work done is the same, we have:
4800 = x × 20
⇒ x = 4800 / 20
⇒ x = 240
The current number of men is 80, so the number of additional men required:
Additional men = 240 - 80
Additional men = 160
The correct answer is option 3.
Single Efficiency Question 7:
Twenty men can finish a work in 30 days. When should 5 men leave the work so that it may be finished in 35 days?
Answer (Detailed Solution Below)
Single Efficiency Question 7 Detailed Solution
Given:
20 men can finish the work in 30 days.
The work needs to be finished in 35 days.
Formula Used:
Work = Men × Days
Calculation:
Total work = 20 men × 30 days = 600 man-days
Let 5 men leave after x days.
Work done by 20 men in x days = 20 men × x days = 20x man-days
Remaining work = 600 man-days - 20x man-days = (600 - 20x) man-days
Remaining men = 20 men - 5 men = 15 men
Remaining days = 35 days - x days
Work to be done by 15 men in (35 - x) days = 15 men × (35 - x) days = 15(35 - x) man-days
Equating the remaining work:
15(35 - x) = 600 - 20x
⇒ 525 - 15x = 600 - 20x
⇒ 5x = 75
⇒ x = 15
5 men should leave after 15 days.
The correct answer is option 4.