Impulse Response MCQ Quiz in मल्याळम - Objective Question with Answer for Impulse Response - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Apr 9, 2025
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Impulse Response Question 1:
Match the pole zero plot of a 2nd order system with their impulse response.
(P) (1) \(c\left( t \right) = \frac{{{\omega _n}}}{{\sqrt {1 - {\xi ^2}} }}{e^{ - {\xi ^{{\omega _n}t}}}}\sin {\omega _n}\sqrt {1 - {\xi ^2}} t\)
(Q) (2) \(c\left( t \right) = {\omega _n}\sin {\omega _n}t\)
(R) (3) \(c\left( t \right) = \omega _n^2t{e^{ - {\omega _n}t}}\)
(S) (4) \(c\left( t \right) = \omega _n^2{e^{ - \left( {\xi {\omega _n} + {\omega _n}\sqrt {{\xi ^2} - 1} } \right)t}}\)
Answer (Detailed Solution Below)
\(\rm P – 2, Q – 4, R – 1, S - 3\)
Impulse Response Question 1 Detailed Solution
Plot (P) has two poles on imaginary axis and hence it’s response consists constant amplitude and frequency of oscillations hence (P) matches to (2).
Plot (Q) has both the poles on real axis hence there is no scope of oscillations and it is having over damped nature hence (Q) matches to (4).
Plot (R) has complex conjugate poles hence there will be oscillations as well as attenuation and system is under damped. So (R) is matching to (1)
Similarly plot (S) has both poles are identical and resulting critically damped system. Hence (S) is matching option (3).