Voltage Regulation MCQ Quiz - Objective Question with Answer for Voltage Regulation - Download Free PDF

Last updated on Jun 10, 2025

Latest Voltage Regulation MCQ Objective Questions

Voltage Regulation Question 1:

A 3-phase, 10 kV distribution line delivers power to a load at a 0.8 power factor lagging. If the current is 50 A, and the load resistance and reactance per km are 0.15 Ω and 0.2 Ω, respectively, for a 400 m line, what is the approximate voltage drop per phase (in V/phase)?

  1. 0 + j10 
  2. 1 + j10
  3. 4.8 + j1.4
  4. 1 + j5 

Answer (Detailed Solution Below)

Option 3 : 4.8 + j1.4

Voltage Regulation Question 1 Detailed Solution

Concept

The voltage drop per phase (in V/phase) is given by:

V = I × ZT

where, V = Voltage drop

I = Current

ZT = Total Impedance

Calculation

Given, cosϕ = 0.8 lag → ϕ = 36.86° 

I = 50∠-36.86° 

Length = 400 m = 0.4 km

ZT = (0.15 + j0.2) × 0.4

ZT = (0.06 + j0.08) Ω/km

V = (50∠-36.86°) × (0.06 + j0.08)

V = 50(0.8 - j0.6) × (0.06 + j0.08)

V = (40 - j30) × (0.06 + j0.08)

V = 4.8 + j1.4

Voltage Regulation Question 2:

A single phase 60 Hz generator supplies an inductive load of 4500kW at a power factor of 0.80 lagging by means of a 20 km long overhead transmission line. The line resistance and inductance are 0.0195 ohm and 0.60 mH per km. The voltage at the receiving end is required to be kept constant at 10.2 kV. Find the voltage regulation of the line.

  1. 12.59%  
  2. 16.34%
  3. 32.68%  
  4. 41.15%

Answer (Detailed Solution Below)

Option 2 : 16.34%

Voltage Regulation Question 2 Detailed Solution

Explanation:

Voltage Regulation of a Transmission Line

Problem Statement:

A single-phase 60 Hz generator supplies an inductive load of 4500 kW at a power factor of 0.80 lagging through a 20 km long overhead transmission line. The line resistance and inductance are 0.0195 ohm and 0.60 mH per km, respectively. The voltage at the receiving end is required to be maintained at 10.2 kV. The task is to calculate the voltage regulation of the line.

Given Data:

  • Power (P): 4500 kW = 4500 × 103 W
  • Power factor (pf): 0.80 (lagging)
  • Receiving end voltage (VR): 10.2 kV = 10.2 × 103 V
  • Line length (L): 20 km
  • Resistance per km (R/km): 0.0195 Ω
  • Inductance per km (L/km): 0.60 mH = 0.60 × 10-3 H
  • Frequency (f): 60 Hz

Step-by-Step Solution:

Step 1: Calculate the receiving end current (IR)

The apparent power (S) is related to the real power (P) and power factor (pf) as:

S = P / pf

Substituting the values:

S = (4500 × 103) / 0.80 = 5625 × 103 VA = 5625 kVA

The current (IR) is given by:

IR = S / (√2 × VR)

Substituting the values:

IR = (5625 × 103) / (√2 ×10.2 ×103)

Voltage Regulation Question 3:

What is the receiving end voltage of a 1.1 kV, single-phase short transmission line delivering 50 A at a lagging power factor of 0.8, if resistance and reactance of the line are 4 Ω and 6 Ω, respectively?

  1. 480 V
  2. 760 V
  3. 940 V
  4. 820 V

Answer (Detailed Solution Below)

Option 2 : 760 V

Voltage Regulation Question 3 Detailed Solution

Concept

The receiving end voltage of a single-phase short transmission line is given by:

\(V_R=V_S-I_R(R+jX)\)

where, VR = Receiving end voltage

V= Sending end voltage

IR = Receiving end current

R = Resistance

X = Inductive Reactance

Calculation

Given, V= 1.1 kV = 1100 kV

IR = 50 ∠-36.86° 

R = 4 Ω 

X = 6 Ω 

\(V_R=1100-(50\angle-36.86)(4+j6)\)

\(V_R=1100-(50\angle-36.86)(7.74\angle 56.30)\)

\(V_R=1100-(387.29\angle 19.44)\)

\(V_R=734.78\space +\space j128.89\)

VR = 760 V

Voltage Regulation Question 4:

Line regulation of short transmission lines is a measure of which of the following?

  1. How much voltage drop occurs along the length of the transmission line.
  2. Reduction due to high operating voltage of the line
  3. Loss of electric potential along the path of current
  4. The ratio of the final power received (PR) to the final power sent (PS), expressed in percentage.

Answer (Detailed Solution Below)

Option 1 : How much voltage drop occurs along the length of the transmission line.

Voltage Regulation Question 4 Detailed Solution

Line regulation for short transmission lines specifically measures how much voltage drop occurs along the length of the transmission line, making it a critical factor in assessing the performance of electrical transmission systems.

Explanation:

  • Line Regulation: Line regulation refers to the ability of a transmission line to maintain a constant voltage level at the receiving end despite variations in load current. It indicates how much the voltage changes as the load on the line changes.
  • Voltage Drop: In short transmission lines, the voltage drop is primarily caused by the resistance and reactance of the line. As the load increases, the current through the line increases, resulting in a greater voltage drop along the length of the line. Line regulation quantifies this drop.
  • Importance of Line Regulation: Good line regulation is crucial for ensuring that consumers receive a stable voltage level, which is essential for the proper functioning of electrical equipment.

Voltage Regulation Question 5:

I, R, XL, VR and cosϕR represent voltage regulation, line current, line resistance, line reactance, receiving end voltage and load power factor of transmission line, respectively. Also, receiving end voltage is more than the sending end voltage. Identify the correct expression for the leading load power factor.

  1. IR COSϕR = IXLCOSϕR 
  2. IR COSϕR > IXLCOSϕR 
  3. IR COSϕR < IXLCOSϕR 
  4. IR COSϕR >> IXLCOSϕR 

Answer (Detailed Solution Below)

Option 3 : IR COSϕR < IXLCOSϕR 

Voltage Regulation Question 5 Detailed Solution

Concept of Voltage Regulation and Power Factor:

Voltage regulation (VR) is defined as the difference between the sending end voltage (VS) and the receiving end voltage (VR), expressed as a fraction of the receiving end voltage:

VR = (VS - VR) / VR

For a leading power factor load, the voltage regulation can be affected by the inductive reactance (XL) and the line resistance (R) of the transmission line. The expression for voltage regulation in terms of these parameters is:

VR = (I R cosϕR) - (I XL sinϕR)

Where,

  • I = Line Current
  • R = Line Resistance
  • XL = Line Reactance
  • VR = Receiving End Voltage
  • cosϕR = Load Power Factor (leading)
     

Given Condition:

  • The receiving end voltage (VR) is more than the sending end voltage (VS), indicating a leading load power factor. This condition implies that the reactive component is capacitive, causing the voltage to rise.
  • In a transmission line with a leading power factor, the voltage regulation is negative, meaning the receiving end voltage (VR) is higher than the sending end voltage. The leading power factor causes the capacitive reactance to dominate, which means the reactive component (IXL) plays a larger role than the resistive component (IR). This leads to the condition where IR COSϕR is less than IXLCOSϕR.
     

Correct Expression for Leading Power Factor: IR cosϕR < I XL cosϕR

Conclusion:

Hence, the correct expression for the leading load power factor is:

IR cosϕR < I XL cosϕR

Top Voltage Regulation MCQ Objective Questions

The percentage voltage regulation of transmission lines is computed as:

(Where s is the sending end; R, receiving end; NL, no-load; FL, full-load)

  1. \(\frac{{\left| {V_S^{FL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{R}}^{{\rm{NL}}}} \right|}} \times 100\)
  2. \(\frac{{\left| {V_R^{NL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}} \times 100\)
  3. \(\frac{{\left| {V_R^{FL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{NL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}} \times 100\)
  4. \(\frac{{\left| {V_s^{FL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{S}}^{{\rm{NL}}}} \right|}} \times 100\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{{\left| {V_R^{NL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}} \times 100\)

Voltage Regulation Question 6 Detailed Solution

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Concept:

Voltage regulation of Transmission line:

  • When a transmission line is carrying a current, there is a voltage drop in the line due to the resistance and inductance of the transmission line.
  • Finally, the receiving end voltage ( V) of the line is generally less than the sending end voltage (VS)
  • The difference in voltage at the receiving end of the transmission line between the conditions of no-load and the full load is called voltage regulation
  • Voltage regulation is expressed as a percentage of the receiving end voltage.


 \(V.R =\frac{V_S - V_R}{V_R} \times 100=\frac{{\left| {V_R^{NL}} \right| - \left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}}{{\left| {{\rm{V}}_{\rm{R}}^{{\rm{FL}}}} \right|}} \times 100\)

Note: At no load, \(|V_S|=|V_R|\)

Which of the following statements is/are true?

a) Feeders are designed from the point of view of its current carrying capacity.

b) Distributors are designed on the basis of voltage drop in it.

c) Voltage variation at the consumers terminal is not considered while designing the distributor.

  1. (b) and (c) only
  2. (a) and (b) only
  3. (a),(b) and (c)
  4. (a) only

Answer (Detailed Solution Below)

Option 2 : (a) and (b) only

Voltage Regulation Question 7 Detailed Solution

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The correct answer is option 2):((a) and (b) only)

Concept:

  • A feeder is a conductor having constant current density. The size of the feeder is designed based on current-carrying capacity. For V ≤ 220 kV, the selection of conductor is done based on the current-carrying capacity.
  • The main criteria for the design of a feeder are its current carrying capacity which accounts for thermal limits rather than voltage drops.
  • A distributor has variable loading along its length due to the service conditions of tapping by the individual consumers. The voltage variation at the consumer end must be kept under ±5%. So, the main criterion for the design of a distribution feeder is voltage regulation or voltage drop.
  • Hence c) Voltage variation at the consumer's terminal is not considered while designing the distributor is wrong

The A, B, C, D constant of a 220 kV line are : A = D = 0.94 ∠1°, B = 130 ∠73°, C = 0.001 ∠90°. If the sending end voltage of the line for a given load delivered at nominal voltage is 240 kV, the % voltage regulation of the line is

  1. 5
  2. 9
  3. 16
  4. 21

Answer (Detailed Solution Below)

Option 3 : 16

Voltage Regulation Question 8 Detailed Solution

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Concept:

Voltage regulation of the transmission line is defined as the ratio of the difference between sending and receiving end voltage to receiving end voltage of a transmission line between conditions of no-load and full load.

It can be expressed in percentage as

\(V.R = \frac{{{V_{RN}} - {V_{RF}}}}{{{V_{RF}}}} \times 100\)

Sending end voltage for the transmission line is given as,

VS =AVr + BIr

Under no-load condition, Ir = 0

Calculation:

Voltage at sending-end,

Vs = AVR + BIR

At no-load, IR = 0

From the given data,

VRF = 220 kV

From the above concept,

\(\begin{array}{l} \Rightarrow {V_{RN}} = \frac{{{V_S}}}{A} = \frac{{240 \times {{10}^3}}}{{0.94}} = 255.3kV\\ \% \ V.R = \frac{{255.3 - 220}}{{220}} \times 100 = 16\% \end{array}\)

The voltage regulation of a shunt transmission line will be maximum when the value of tan ϕ for lagging power factor is

  1. Unity
  2. Zero
  3. \(\dfrac{R}{X}\)
  4. \(\dfrac{X}{R}\)

Answer (Detailed Solution Below)

Option 4 : \(\dfrac{X}{R}\)

Voltage Regulation Question 9 Detailed Solution

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Concept:

Voltage regulation of transmission line is defined as the ratio of the difference between sending and receiving end voltage to receiving end voltage of a transmission line between conditions of no-load and full load.

It can be expressed in percentage as

\(\% VR = \frac{{{V_s} - {V_R}}}{{{V_R}}} \times 100\)

Where Vs is the sending end voltage per phase and VR is the receiving end voltage per phase.

Percent regulation, \(= \frac{{IRcos{\phi _r} \pm IXsin{\phi _r}}}{{{V_r}}} \times 100\;\)

Application:

Maximum regulation occurs at lagging power factor only

\(\frac{d}{{d\phi }}\left( {R\cos \phi + X\sin \phi } \right) = 0\)

\( \Rightarrow \tan \phi = \frac{X}{R}\)

Additional Information

Zero regulation occurs at leading power factor only

\(\Rightarrow \frac{{IRcos{\phi _r} - IXsin{\phi _r}}}{{{V_r}}} \times 100 = 0\;\)

\(\Rightarrow IRcos{\phi _r} = IXsin{\phi _r}\)

\(\Rightarrow {\phi _r} = {\tan ^{ - 1}}\left( {\frac{R}{X}} \right)=\frac{\pi}{2}-\theta \;\)

In a short transmission line, the reactance and resistance are equal. Find the characteristics of the load, if the voltage regulation is zero.

  1. 0.707 leading
  2. 0.707 lagging
  3. 0.866 lagging
  4. 0.866 leading

Answer (Detailed Solution Below)

Option 1 : 0.707 leading

Voltage Regulation Question 10 Detailed Solution

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The correct answer is option 1): (0.707 leading)

Concept:

  • In a short transmission line, the length of the line is below 80 km, and the line voltage is comparatively low (below 69 kV). Hence the capacitance effects of the line are extremely small and thus neglected.
  • Voltage regulation = \(= \frac{{IRcos{\phi _r} \pm IXsin{\phi _r}}}{{{V_r}}} \times 100\;\)

For zero voltage regulation,

IV(Rcos⁡ϕ−Xsin⁡ϕ) = 0 (leading power factor)

⇒ tan ϕ = \( R\over X\) If R = X,

then tan ϕ = 1 ⇒ ϕ = 45°

Power factor, cos ϕ = cos 45°= 0.707 leading power factor​

A power supply has a full load voltage of 24 V. It's no load voltage for 5% regulation is :

  1. 29 V
  2. 25.2 V
  3. 22.8 V
  4. 19 V

Answer (Detailed Solution Below)

Option 2 : 25.2 V

Voltage Regulation Question 11 Detailed Solution

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The correct answer is option 2):(25.2 V)

Concept:

The percentage regulation is defined as:

\(\%~R = \frac{{({V_{NL}} - {V_{FL}})}}{{{V_{FL}}}}\times\;100\;\%\)

VNL = No load voltage

VFL = Full load voltage

Calculation:

\(\frac{5}{{100}} = \frac{{({V_{NL}} - 24)}}{{24}}\)

\(\frac{5}{{100}}.\left( {24} \right) = ({V_{NL}} - 24)\)

VNL = 25.2 V

The condition for zero voltage regulation in a transmission line is:

[R = resistance of transmission line

X = reactance of transmission line

Z = impedance of transmission line]

  1. Cos θ = ±Z/R
  2. Cos θ = ±R/Z
  3. Cos θ = ±X/Z
  4. Cos θ = ±Z/X

Answer (Detailed Solution Below)

Option 3 : Cos θ = ±X/Z

Voltage Regulation Question 12 Detailed Solution

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Condition for Zero and Maximum Voltage Regulation

  • Voltage regulation is a measure of the change in the voltage magnitude between the sending and receiving end of a component from no load to full load as a percentage of full load voltage.
  • During the calculation of voltage regulation, we only deal with the magnitude of quantities not along with phasor.

Voltage regulation is given by this approximation 

V.R. = \(\rm \left(\frac{I_R}{V_R}\right)[R\cos ϕ_R\pm X \sin ϕ_R]\)

V.R. = \(\rm \left(\frac{I_R}{V_R}\right)\times\sqrt{R^2+X^2}\left[\frac{R}{\sqrt{R^2+X^2}}\cosϕ_R\pm \frac{X}{\sqrt{R^2+X^2}}\sin ϕ_R\right]\)

\(\rm \cos θ=\frac{R}{\sqrt{R^2+X^2}}\) and \(\rm \sin θ=\frac{X}{\sqrt{R^2+X^2}}\)

\(\rm \tanθ=\frac{X}{R}\)

\(\rm Z_{eq}(pu)=\frac{\sqrt{R^2+X^2}}{\left(\frac{V_R}{I_R}\right)}\)

V.R. = Zeq(pu) cos (θ - ϕR) → for lagging loads

V.R. = Zeq(pu) cos (θ + ϕR) → for leading loads

Condition for Zero Voltage Regulation

  • Zero voltage regulation means, Sending end voltage and Receiving end voltage become equal.
  • This case is also known as the ideal voltage regulation. Ideal voltage regulation is desirable in a power system but not possible practically.
  • Zero voltage regulation can only be achieved when the nature of the load is of leading.

⇒ V.R. = 0 ⇒ At leading loads

V.R. = Zeq(pu) cos (θ + ϕR)

Zeq(pu) cos (θ + ϕR) = 0

cos (θ + ϕR) = 0

(θ + ϕR) = 90°

ϕR = 90° - θ

cos ϕR = cos (90° - θ) = sin θ

\(\rm \sin θ =\frac{X}{\sqrt{R^2+X^2}}\)

Value of the receiving end power factor in order to achieve the zero voltage regulation is given below:

⇒ \(\rm \cosϕ_R =\frac{X}{\sqrt{R^2+X^2}}\) (Leading load)

Condition for Maximum Voltage Regulation

  • Maximum voltage regulation means the difference between the receiving end voltage and the sending end becomes very large and such a case can only happen when the nature of the load is of lagging.
  • The expression of voltage regulation for a lagging load is given below:

V.R. = Zeq(pu) cos (θ - ϕR)

The maximum value of cosine function occurs when its argument becomes equal to 0°

cos (θ - ϕR) = 1

θ - ϕR​ = 1

ϕR​ = θ

\(\rm \cos\phi_R=\cos \theta=\frac{R}{\sqrt{R^2+X^2}}\)

% Voltage Regulation vs Power Factor

Now we can conclude various things in relation to the voltage regulation and the power factor which are mentioned below one by one:

1. Zero voltage regulation is possible only for leading power factor load.

2. Maximum voltage regulation is possible only when the load is of lagging or inductive nature.

3. For leading loads, voltage regulation can be zero, positive or negative.

4. For lagging loads, voltage regulation is always positive.

F2 Madhuri Engineering 27.01.2023 D1

In transmission lines, variation in voltage at the receiving end, expressed as a percentage of full load voltage at the receiving end, when full load at a given power factor is removed with voltage at the sending end being kept constant is called:

  1. Voltage regulation
  2. Load regulation
  3. Shunt regulation
  4. Current regulation

Answer (Detailed Solution Below)

Option 1 : Voltage regulation

Voltage Regulation Question 13 Detailed Solution

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The correct answer is option 1.

Voltage regulation

“Voltage regulation is defined as the ratio of the difference between sending and receiving end voltage to receiving end voltage of a transmission line between the conditions of no load and full load”.

\(VR={V_{R(no \space load)}-V_{R(full\space load)}\over V_R}\)

The receiving end voltage at no-load condition is given by:

\(V_S=AV_R+BI_R\)

At no-load, IR = 0

\(V_S=AV_R+BI(0)\)

\(V_{R(no\space load)}={V_S\over A}\)

and \(V_{R(full\space load)}=V_R\)

The expression for the voltage regulation in the transmission line is:

\(VR={{V_{S}\over A}-V_{R}\over V_R}\)

In order to improve the voltage regulation of a supply system, wires used in wiring the system should have ______.

  1. High insulation resistance
  2. More area of cross section
  3. Less area of cross section
  4. More specific resistance

Answer (Detailed Solution Below)

Option 2 : More area of cross section

Voltage Regulation Question 14 Detailed Solution

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  • Voltage regulation is a measure of the change in voltage magnitude between the sending and receiving end of the component.
  • It is commonly used in power engineering to describe the percentage voltage difference between no-load and full-load voltages distribution lines, transmission lines, and transformers.
  • Voltage drop occurs when the voltage at the end of a run of calls is lower than at the beginning.
  • Any length or size of wires will have the same resistance and running a current through this dc resistance will cause the voltage to drop.
  • As the length of the cable increases, so does its resistance and reactance increase in proportion.
  • Hence, the voltage drop is particularly problematic with long cable runs, for example in larger buildings or on more significant properties such as forms.
  • Electrical cables carrying current always present inherent resistance, or impedance, to the flow of current.
  • Voltage drop is measured as the amount of voltage loss that occurs through all or part of a circuit due to cable ‘impedance’ in volts.
  • A larger voltage drop in a cable cross-sectional area can cause lights to flicker or XYZ lively, heaters to heat poorly, and motors to run hotter than normal and turn out.
  • This condition causes the load to work harder with less voltage pushing the current.
  • To improve voltage regulation (or to decrease voltage drop) in a circuit, one needs to increase the cross-sectional size of the conductors. This is done to lower the overall resistance of the cable length.


Note:

Larger copper or aluminum cable sizes increases cost, so its important to calculate voltage drop and find the optimum voltage wire size that will reduce voltage drop to safe levels while remaining cost-effective.

I, R, XL, VR and cosϕR represent voltage regulation, line current, line resistance, line reactance, receiving end voltage and load power factor of transmission line, respectively. Also, receiving end voltage is more than the sending end voltage. Identify the correct expression for the leading load power factor.

  1. IR COSϕR = IXLCOSϕR 
  2. IR COSϕR > IXLCOSϕR 
  3. IR COSϕR < IXLCOSϕR 
  4. IR COSϕR >> IXLCOSϕR 

Answer (Detailed Solution Below)

Option 3 : IR COSϕR < IXLCOSϕR 

Voltage Regulation Question 15 Detailed Solution

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Concept of Voltage Regulation and Power Factor:

Voltage regulation (VR) is defined as the difference between the sending end voltage (VS) and the receiving end voltage (VR), expressed as a fraction of the receiving end voltage:

VR = (VS - VR) / VR

For a leading power factor load, the voltage regulation can be affected by the inductive reactance (XL) and the line resistance (R) of the transmission line. The expression for voltage regulation in terms of these parameters is:

VR = (I R cosϕR) - (I XL sinϕR)

Where,

  • I = Line Current
  • R = Line Resistance
  • XL = Line Reactance
  • VR = Receiving End Voltage
  • cosϕR = Load Power Factor (leading)
     

Given Condition:

  • The receiving end voltage (VR) is more than the sending end voltage (VS), indicating a leading load power factor. This condition implies that the reactive component is capacitive, causing the voltage to rise.
  • In a transmission line with a leading power factor, the voltage regulation is negative, meaning the receiving end voltage (VR) is higher than the sending end voltage. The leading power factor causes the capacitive reactance to dominate, which means the reactive component (IXL) plays a larger role than the resistive component (IR). This leads to the condition where IR COSϕR is less than IXLCOSϕR.
     

Correct Expression for Leading Power Factor: IR cosϕR < I XL cosϕR

Conclusion:

Hence, the correct expression for the leading load power factor is:

IR cosϕR < I XL cosϕR

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