Plant Use Factor MCQ Quiz - Objective Question with Answer for Plant Use Factor - Download Free PDF

Last updated on Jun 19, 2025

Latest Plant Use Factor MCQ Objective Questions

Plant Use Factor Question 1:

A power plant has a rated capacity of 200 MW and operates for 10 hours per day throughout the year, generating 365,000 MWh. What is the Plant Use Factor?

  1. 85%
  2. 50%
  3. 70%
  4. 90%

Answer (Detailed Solution Below)

Option 2 : 50%

Plant Use Factor Question 1 Detailed Solution

Explanation:

Plant Use Factor (PUF):

Definition: The Plant Use Factor (PUF) is a performance metric used to evaluate the utilization of a power plant's capacity. It represents the ratio of the actual energy generated by the power plant over a specific period of time to the maximum possible energy that could have been generated if the plant operated continuously at its rated capacity during the same period.

Mathematical Formula:

The Plant Use Factor (PUF) can be calculated using the following formula:

PUF = (Actual Energy Generated) ÷ (Maximum Possible Energy)

Where:

  • Actual Energy Generated: The total energy generated by the plant over the given period (in MWh).
  • Maximum Possible Energy: The energy that the plant could have generated if it operated at its rated capacity for the total time period (in MWh).

Given Data:

  • Rated Capacity of the Power Plant = 200 MW
  • Daily Operating Hours = 10 hours
  • Number of Days in a Year = 365 days
  • Actual Energy Generated = 365,000 MWh

Step-by-Step Solution:

Step 1: Calculate the Maximum Possible Energy

The maximum possible energy is calculated based on the rated capacity and the actual operating hours of the power plant over the year:

Maximum Possible Energy = Rated Capacity × Daily Operating Hours × Number of Days in a Year

Substitute the given values:

Maximum Possible Energy = 200 MW × 10 hours/day × 365 days

Maximum Possible Energy = 730,000 MWh

Step 2: Calculate the Plant Use Factor (PUF)

Using the formula for PUF:

PUF = (Actual Energy Generated) ÷ (Maximum Possible Energy)

Substitute the values:

PUF = 365,000 MWh ÷ 730,000 MWh

PUF = 0.5

Step 3: Convert to Percentage (if necessary)

The Plant Use Factor is often expressed as a decimal or percentage. In this case, the result is already in decimal form, and the PUF is 0.5, or 50%.

Final Answer:

The Plant Use Factor is 0.5. Therefore, the correct option is Option 2.

Important Information:

To further understand the analysis, let’s evaluate the other options:

Option 1: PUF = 0.85

This option is incorrect. A Plant Use Factor of 0.85 would imply that the power plant is operating at 85% of its maximum possible energy generation. However, based on the calculations, the actual PUF is 0.5, which is significantly lower than 0.85.

Option 3: PUF = 0.7

This option is also incorrect. A Plant Use Factor of 0.7 suggests that the plant is utilizing 70% of its maximum possible capacity. However, the calculations clearly show that the actual PUF is 0.5, not 0.7.

Option 4: PUF = 0.9

This option is incorrect as well. A PUF of 0.9 would mean that the power plant is operating at 90% of its maximum possible capacity. This is much higher than the actual calculated PUF of 0.5.

Option 5: No value provided.

This option is irrelevant as it does not provide any specific value for the PUF, and it is not the correct answer.

Conclusion:

The Plant Use Factor is an essential metric for assessing the efficiency and utilization of a power plant. In this case, the PUF was calculated to be 0.5, indicating that the plant generates half of the energy it could potentially generate if operated at full capacity for its operating hours. This value highlights the importance of analyzing operational patterns and identifying potential areas for efficiency improvement in power plant management.

Plant Use Factor Question 2:

A generating plant has an installed capacity of 20 MW and produces 20 × 106 kWh. What is the plant use factor if it operates for 4000 hours in a year?

  1. 0.75
  2. 0.5
  3. 0.15
  4. 0.25

Answer (Detailed Solution Below)

Option 4 : 0.25

Plant Use Factor Question 2 Detailed Solution

Concept

The Plant Use Factor is calculated using the formula:

\(Plant \space use \space factor={Actual \space Energy \space Produced \over Installed \space capacity \times Operating \space hours}\)

Calculation

Given, Installed capacity = 20 MW

Energy generated = 20 × 106 kWh

Operating hours = 4000 hours

\(Plant \space use \space factor={20\times 10^6 \times 10^3 \over 20\times 10^6\times4000} \)

Plant Use Factor = 0.25

Plant Use Factor Question 3:

The ratio of energy produced in a given time to the maximum possible energy that can be produced is:

  1. Load factor
  2. Plant use factor
  3. Demand factor
  4. Utilization factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 3 Detailed Solution

Plant use factor

It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

\(Plant \space use\space factor={Produced \space energy \over Maximum \space energy}\)

Demand Factor

​The demand factor of an electric power station is defined as the ratio of maximum demand on the power station to its connected load.

\(Demand \space factor={Maximum \space demand \over Connected \space demand}\)

Load Factor

Load factor is defined as the ratio of the average load over a given period to the maximum demand (peak load) occurring in that period.

\(Load \space factor={Average \space demand \over Maximum \space demand}\)

Diversity Factor

The ratio of the sum of individual maximum demands to the maximum demand on the power station is known as a diversity factor.

\(Diversity \space factor={Sum\space of \space individual \space maximum \space demand \over Maximum \space demand}\)

Plant Use Factor Question 4:

The ratio of energy produced by a power plant to the installed capacity of the plant is called as

  1. Plant load factor
  2. Plant use factor
  3. Average load factor
  4. Demand factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 4 Detailed Solution

Explanation:

Plant Use Factor:

  • The plant use factor is the ratio of energy produced by a power plant to the installed capacity of the plant.

\(Plant~use~factor = \frac{Station~output~in~KWh}{Plant~ capacity~\times~hour~of~use} \)

Plant Load Factor:

  • The plant load factor is the ratio of average power generated by the plant to the maximum power that could have been generated for a given period.
  • It is an indicator of efficiency.
  • Coal-based power plants in India run at an average of 56.5 % plant load factor.

Demand Factor:

  • The demand factor is the ratio of maximum demand on the power station to its connected load.
  • The value of the demand factor is usually less than 1. It is because maximum demand is always less than the connected demand. The knowledge of the demand factor is vital in determining the capacity of the plant equipment.

Average Load Factor:

  • The area under the daily load curve dived by the total number of hours gives the average load on the station.

\(Average~load~=~\frac{Area~(in~KWh)~under ~daily ~load~curve}{24~hours}\)

F2 Savita Engineering 19-4-22 D6

Plant Use Factor Question 5:

Suppose a plant that has installed capacity of 20 MW produces annual output of 7.35 × 106 kWh and remains in operation for 2190 hours in a year. Find the plant use factor.

  1. 14.5%
  2. 16.7%
  3. 18.5%
  4. 25.5%

Answer (Detailed Solution Below)

Option 2 : 16.7%

Plant Use Factor Question 5 Detailed Solution

Concept:

Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.

\(Plant\;use\;factor = \frac{{Station\;output\;}}{{Plant\;capacity \times hours\;of\;use}}\)

Calculation:

Given that, station output = 7.35 × 106 kWh = 7.35 × 103 MWh

Plant capacity = 20 MW

Hours of use = 2190

Plant use factor \( = \frac{{7.35 \times {{10}^3}}}{{20 \times 2190}} \times 100 = 16.78\% \)

Top Plant Use Factor MCQ Objective Questions

Suppose a plant that has installed capacity of 20 MW produces annual output of 7.35 × 106 kWh and remains in operation for 2190 hours in a year. Find the plant use factor.

  1. 14.5%
  2. 16.7%
  3. 18.5%
  4. 25.5%

Answer (Detailed Solution Below)

Option 2 : 16.7%

Plant Use Factor Question 6 Detailed Solution

Download Solution PDF

Concept:

Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.

\(Plant\;use\;factor = \frac{{Station\;output\;}}{{Plant\;capacity \times hours\;of\;use}}\)

Calculation:

Given that, station output = 7.35 × 106 kWh = 7.35 × 103 MWh

Plant capacity = 20 MW

Hours of use = 2190

Plant use factor \( = \frac{{7.35 \times {{10}^3}}}{{20 \times 2190}} \times 100 = 16.78\% \)

Plant use factor is

  1. Maximum demand/Connected load
  2. Number of units generated/(Plant capacity × number of hours plant operated)
  3. Average demand/plant capacity
  4. Average load/Maximum load

Answer (Detailed Solution Below)

Option 2 : Number of units generated/(Plant capacity × number of hours plant operated)

Plant Use Factor Question 7 Detailed Solution

Download Solution PDF

Plant capacity factor: It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

\(Plant\;capacity\;factor = \frac{{{\rm{Actual\;energy\;produced}}}}{{Maximum\;energy\;that\;could\;have\;been\;produced}}\)

\( = \frac{{Average\;demand \times T}}{{Plant\;capacity \times 100}}\)

\(= \frac{{Average\;demand}}{{Plant\;capacity}}\)

\(Annual\;plant\;capacity\;factor = \frac{{{\rm{Annual\;kWh\;output}}}}{{Plant\;capacity \times 8760}}\)

The plant capacity factor is an indication of the reverse capacity of the plant. A power station is so designed that it has some reserve capacity for meeting the increased load demand in future. Therefore, the installed capacity of the plant is always somewhat greater than the maximum demand on the plant.

Reserve capacity = Plant capacity – Maximum demand

If the maximum demand on the plant is equal to plant capacity, then load factor and plant capacity factor will have the same value. In such a case, the plant will have no reserve capacity.

Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.

\(Plant\;use\;factor = \frac{{Station\;output\;in\;kWh}}{{Plant\;capacity \times hours\;of\;use}}\)

Capacity factor = Load factor × plant use factor

The ratio of energy produced in a given time to the maximum possible energy that can be produced is:

  1. Load factor
  2. Plant use factor
  3. Demand factor
  4. Utilization factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 8 Detailed Solution

Download Solution PDF

Plant use factor

It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

\(Plant \space use\space factor={Produced \space energy \over Maximum \space energy}\)

Demand Factor

​The demand factor of an electric power station is defined as the ratio of maximum demand on the power station to its connected load.

\(Demand \space factor={Maximum \space demand \over Connected \space demand}\)

Load Factor

Load factor is defined as the ratio of the average load over a given period to the maximum demand (peak load) occurring in that period.

\(Load \space factor={Average \space demand \over Maximum \space demand}\)

Diversity Factor

The ratio of the sum of individual maximum demands to the maximum demand on the power station is known as a diversity factor.

\(Diversity \space factor={Sum\space of \space individual \space maximum \space demand \over Maximum \space demand}\)

A generating plant has an installed capacity of 20 MW and produces 20 × 106 kWh. What is the plant use factor if it operates for 4000 hours in a year?

  1. 0.75
  2. 0.5
  3. 0.15
  4. 0.25

Answer (Detailed Solution Below)

Option 4 : 0.25

Plant Use Factor Question 9 Detailed Solution

Download Solution PDF

Concept

The Plant Use Factor is calculated using the formula:

\(Plant \space use \space factor={Actual \space Energy \space Produced \over Installed \space capacity \times Operating \space hours}\)

Calculation

Given, Installed capacity = 20 MW

Energy generated = 20 × 106 kWh

Operating hours = 4000 hours

\(Plant \space use \space factor={20\times 10^6 \times 10^3 \over 20\times 10^6\times4000} \)

Plant Use Factor = 0.25

The ratio of energy produced by a power plant to the installed capacity of the plant is called as

  1. Plant load factor
  2. Plant use factor
  3. Average load factor
  4. Demand factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 10 Detailed Solution

Download Solution PDF

Explanation:

Plant Use Factor:

  • The plant use factor is the ratio of energy produced by a power plant to the installed capacity of the plant.

\(Plant~use~factor = \frac{Station~output~in~KWh}{Plant~ capacity~\times~hour~of~use} \)

Plant Load Factor:

  • The plant load factor is the ratio of average power generated by the plant to the maximum power that could have been generated for a given period.
  • It is an indicator of efficiency.
  • Coal-based power plants in India run at an average of 56.5 % plant load factor.

Demand Factor:

  • The demand factor is the ratio of maximum demand on the power station to its connected load.
  • The value of the demand factor is usually less than 1. It is because maximum demand is always less than the connected demand. The knowledge of the demand factor is vital in determining the capacity of the plant equipment.

Average Load Factor:

  • The area under the daily load curve dived by the total number of hours gives the average load on the station.

\(Average~load~=~\frac{Area~(in~KWh)~under ~daily ~load~curve}{24~hours}\)

F2 Savita Engineering 19-4-22 D6

Plant Use Factor Question 11:

Suppose a plant that has installed capacity of 20 MW produces annual output of 7.35 × 106 kWh and remains in operation for 2190 hours in a year. Find the plant use factor.

  1. 14.5%
  2. 16.7%
  3. 18.5%
  4. 25.5%

Answer (Detailed Solution Below)

Option 2 : 16.7%

Plant Use Factor Question 11 Detailed Solution

Concept:

Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.

\(Plant\;use\;factor = \frac{{Station\;output\;}}{{Plant\;capacity \times hours\;of\;use}}\)

Calculation:

Given that, station output = 7.35 × 106 kWh = 7.35 × 103 MWh

Plant capacity = 20 MW

Hours of use = 2190

Plant use factor \( = \frac{{7.35 \times {{10}^3}}}{{20 \times 2190}} \times 100 = 16.78\% \)

Plant Use Factor Question 12:

Plant use factor is

  1. Maximum demand/Connected load
  2. Number of units generated/(Plant capacity × number of hours plant operated)
  3. Average demand/plant capacity
  4. Average load/Maximum load

Answer (Detailed Solution Below)

Option 2 : Number of units generated/(Plant capacity × number of hours plant operated)

Plant Use Factor Question 12 Detailed Solution

Plant capacity factor: It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

\(Plant\;capacity\;factor = \frac{{{\rm{Actual\;energy\;produced}}}}{{Maximum\;energy\;that\;could\;have\;been\;produced}}\)

\( = \frac{{Average\;demand \times T}}{{Plant\;capacity \times 100}}\)

\(= \frac{{Average\;demand}}{{Plant\;capacity}}\)

\(Annual\;plant\;capacity\;factor = \frac{{{\rm{Annual\;kWh\;output}}}}{{Plant\;capacity \times 8760}}\)

The plant capacity factor is an indication of the reverse capacity of the plant. A power station is so designed that it has some reserve capacity for meeting the increased load demand in future. Therefore, the installed capacity of the plant is always somewhat greater than the maximum demand on the plant.

Reserve capacity = Plant capacity – Maximum demand

If the maximum demand on the plant is equal to plant capacity, then load factor and plant capacity factor will have the same value. In such a case, the plant will have no reserve capacity.

Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.

\(Plant\;use\;factor = \frac{{Station\;output\;in\;kWh}}{{Plant\;capacity \times hours\;of\;use}}\)

Capacity factor = Load factor × plant use factor

Plant Use Factor Question 13:

The ratio of energy produced in a given time to the maximum possible energy that can be produced is:

  1. Load factor
  2. Plant use factor
  3. Demand factor
  4. Utilization factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 13 Detailed Solution

Plant use factor

It is the ratio of actual energy produced to the maximum possible energy that could have been produced during a given period.

\(Plant \space use\space factor={Produced \space energy \over Maximum \space energy}\)

Demand Factor

​The demand factor of an electric power station is defined as the ratio of maximum demand on the power station to its connected load.

\(Demand \space factor={Maximum \space demand \over Connected \space demand}\)

Load Factor

Load factor is defined as the ratio of the average load over a given period to the maximum demand (peak load) occurring in that period.

\(Load \space factor={Average \space demand \over Maximum \space demand}\)

Diversity Factor

The ratio of the sum of individual maximum demands to the maximum demand on the power station is known as a diversity factor.

\(Diversity \space factor={Sum\space of \space individual \space maximum \space demand \over Maximum \space demand}\)

Plant Use Factor Question 14:

A generating plant has an installed capacity of 20 MW and produces 20 × 106 kWh. What is the plant use factor if it operates for 4000 hours in a year?

  1. 0.75
  2. 0.5
  3. 0.15
  4. 0.25

Answer (Detailed Solution Below)

Option 4 : 0.25

Plant Use Factor Question 14 Detailed Solution

Concept

The Plant Use Factor is calculated using the formula:

\(Plant \space use \space factor={Actual \space Energy \space Produced \over Installed \space capacity \times Operating \space hours}\)

Calculation

Given, Installed capacity = 20 MW

Energy generated = 20 × 106 kWh

Operating hours = 4000 hours

\(Plant \space use \space factor={20\times 10^6 \times 10^3 \over 20\times 10^6\times4000} \)

Plant Use Factor = 0.25

Plant Use Factor Question 15:

The ratio of energy produced by a power plant to the installed capacity of the plant is called as

  1. Plant load factor
  2. Plant use factor
  3. Average load factor
  4. Demand factor

Answer (Detailed Solution Below)

Option 2 : Plant use factor

Plant Use Factor Question 15 Detailed Solution

Explanation:

Plant Use Factor:

  • The plant use factor is the ratio of energy produced by a power plant to the installed capacity of the plant.

\(Plant~use~factor = \frac{Station~output~in~KWh}{Plant~ capacity~\times~hour~of~use} \)

Plant Load Factor:

  • The plant load factor is the ratio of average power generated by the plant to the maximum power that could have been generated for a given period.
  • It is an indicator of efficiency.
  • Coal-based power plants in India run at an average of 56.5 % plant load factor.

Demand Factor:

  • The demand factor is the ratio of maximum demand on the power station to its connected load.
  • The value of the demand factor is usually less than 1. It is because maximum demand is always less than the connected demand. The knowledge of the demand factor is vital in determining the capacity of the plant equipment.

Average Load Factor:

  • The area under the daily load curve dived by the total number of hours gives the average load on the station.

\(Average~load~=~\frac{Area~(in~KWh)~under ~daily ~load~curve}{24~hours}\)

F2 Savita Engineering 19-4-22 D6

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