Answer (Detailed Solution Below)

Option 2 : 2
Free
Agniveer Navy SSR Full Test - 01
100 Qs. 100 Marks 60 Mins

Detailed Solution

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Concept:

|x| ≥ 0 for every x ∈ R

Calculation:

Let f(x) = |x - 4| + 2

As we know that |x| ≥ 0 for every x ∈ R

∴ |x - 4| ≥ 0

The minimum value of function is attained when |x - 4| = 0

Hence, Minimum value of f(x) = 0 + 2 = 2 

Alternate Method

f(x) =  |x - 4| + 2

There is one critical point i.e. x = 4

f(4) = |4 - 4| + 2

= 0 + 2

= 2

Hence 2 is the minimum value of f(x).

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