Using strain energy method, the vertical deflection at O is (take modulus of elasticity, E = 2 × 105 N/mm2, cross-sectional area of wire, A = 100 mm2).

This question was previously asked in
MPPSC AE CE 2016 Official Paper - II
View all MPPSC AE Papers >
  1. 2.12 mm
  2. 21.2 mm
  3. 1.50 mm
  4. 15.0 mm

Answer (Detailed Solution Below)

Option 1 : 2.12 mm
Free
MPPSC AE Civil (Important Topics): Mini Mock Test
20 Qs. 60 Marks 25 Mins

Detailed Solution

Download Solution PDF

Concept:

The strain energy stored in truss,

U = UOA + UOB

The deflection at O will be, 

Calculation:

At joint O

ΣFx = 0, FOA = FOB..............(i)

ΣFy = 0, FOA × cosθ + FOB × cosθ = P ..........(ii)

2FOA × cosθ = P

Here, cosθ = 3/4.24 and P = 10 kN

The strain energy stored in truss,

U = UOA + UOB

⇒ 

The deflection at O will be, 

Latest MPPSC AE Updates

Last updated on Jul 8, 2025

-> MPPSC AE exam date 2025 will be conducted in July. 

-> Successfully registered candidates will be issued the MPPSC Assistant Engineer admit card 2025

-> MPPSC AE 2025 Notification was released on 31st December, 2024. Candidates can apply online starting from 14th March to 13th April, 2025 (12:00 pm).

-> A total of 23 vacancies of Assistant Engineers (AE) in the Civil, Mechanical and Electrical disciplines have been announced.

-> Candidates will be shortlisted on the basis of the MPPSC State Engineering Services Exam. 

->  Candidates who will be selected will finally get a salary range between Rs. 15,600 to RS. 39,100/-.

-> With Degree in Engineering as the basic educational qualification, it is a great opportunity for various job seekers.

-> Candidates appearing in the exam can refer to the MPPSC AE syllabus and exam pattern for their preparations. 

-> Applicants can practice MPPSC AE previous year question papers to ace the exam with a good score. 

Hot Links: teen patti palace teen patti gold new version teen patti all teen patti star teen patti casino