Two types silver items sold in shop A, x and y. Number of x type silver items sold in shop A is 3m + 2 and number of y type silver items sold in shop A is 2n + 6. Sum of m and n is 10. Find the ratio between m and n?

Question

Question

The line graph shows the number of copper and bronze items sold in four different shops [A, B, C, and D].

The given table shows the ratio between total number of [ copper + bronze] items sold to number silver items sold.

Shop	Ratio between total number of [ copper + bronze] items sold to number silver items sold.
A	5:4
B	29:12
C	25:18
D	3:2

This question was previously asked in

RRB Clerk Mains Memory Based Paper (Held On: 6 October 2024 Shift 1)

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Answer 1

Common Calculation

For shop A,

Number of copper items sold in shop A is 24.

Number of bronze items sold in shop A is 16.

So, total number of copper and bronze items sold in shop A is 24 + 16 = 40.

So, Ratio between total number of [ copper + bronze] items sold to number silver items sold.

So, Number of silver items sold in shop A is 40 × 4 /5 = 32

Similarly, we can calculate others values also, which is given in the table.

Calculation

In Shop A:

Total silver items = 32

Number of x-type silver items = 3m + 2

Number of y-type silver items = 2n + 6

So,

3m + 2 + 2n + 6 = 32

⇒ 3m + 2n = 24

Also, m + n = 10,

So, m = 4 and n = 6

⇒ Required ratio m : n

Answer: m : n = 4 : 6 = 2 : 3