The velocity of electromagnetic waves in a dielectric medium with relative permittivity of 4 will

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SDSC ISRO Technical Assistant Electronics 8 April 2018 Official Paper
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  1. 3 × 108 m/s
  2. 6 × 108 m/s
  3. 1.5 × 108 m/s
  4. 0.75 × 108 m/s

Answer (Detailed Solution Below)

Option 3 : 1.5 × 108 m/s
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Detailed Solution

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Concept:

The velocity (Vp) of a plane electromagnetic wave is given as-

\({V_p} = \frac{1}{{\sqrt {μ \varepsilon } }}\)

Here, μ = μoμr

ε = εo εr

\({v_p} = \frac{1}{{\sqrt {{μ _o}{μ _r}{\varepsilon _o}{\varepsilon _r}} }}\)

\({v_p} = \frac{c}{{\sqrt {{μ _r}{\varepsilon _r}} }}\)-----(1)

\(c = \frac{1}{{\sqrt {{μ _o}{\varepsilon _o}} }} = 3 \times {10^8}\;m/sec\)

μ0 = permeability in free space 4π × 10-7 H/m

εo = permittivity in free space 8.854 × 10-12 C2/Nm2

Calculation:

Given:

μr = 4

From Equation (1):

\(v_p=\frac{3\times10^8}{\sqrt4}\)

vp = 1.5 x 108 m/sec

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