Question
Download Solution PDFThe ratio of the moment of inertia of a circular plate and that of a square plate for equal depth is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Moment of inertia (I1) of circular plate of diameter “D” is given by:
\({I_1} = \frac{\pi }{{64}}*{D^4}\)
Moment of inertia (I2) of square plate of side equal to diameter “D” of circular plate is given by:
\({I_2} = \frac{{{D^4}}}{{12}}\)
\(\frac{{{I_1}}}{{{I_2}}} = \;\frac{{3\pi }}{{16}} = 0.589 < 1\)
Last updated on Jun 24, 2025
-> WBPSC JE recruitment 2025 notification will be released soon.
-> Candidates with a Diploma in the relevant engineering stream are eligible forJunior Engineer post.
-> Candidates appearing in the exam are advised to refer to the WBPSC JE syllabus and exam pattern for their preparations.
-> Practice WBPSC JE previous year question papers to check important topics and chapters asked in the exam.