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VITEEE PYP_125Qs150Min125Marks
Answer (Detailed Solution Below)
Option 4 : 4e3x + 3e−4y = 7
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JEE Main 2025 (Session II) All India Live Test
75 Qs.
300 Marks
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Detailed Solution
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log
dy ⋅ e-4y = e3x dx
when x = 0, y = 0
c =
-3e-4y = 4e3x - 7
4e3x + 3e-4y = 7
Hence option 4 is correct
Last updated on Jul 3, 2025
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