The midpoint of a rigid link of a mechanism moves as a translation along a straight line, from rest, with a constant acceleration of 5 m/s2. The distance covered by the said midpoint in 5 s of motion is

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ESE Mechanical 2018 Official Paper
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  1. 124.2 m
  2. 112.5 m
  3. 96.2 m
  4. 62.5 m

Answer (Detailed Solution Below)

Option 4 : 62.5 m
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

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Concept:

Distance covered by translation, 

u is the initial motion, t is the time and a is the acceleration

Calculation:

Given u = 0, a = 5 m/s2 and t = 5 s

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