The impulse response h[n] of an LTI system is

h[n] = u[n + 3] + u[n - 2] - 2u[n - 7].

Then the system is:

1. Stable

2. Casual

3. Unstable

4. Not casual.

Which of these are correct?

This question was previously asked in
ESE Electronics 2010 Paper 2: Official Paper
View all UPSC IES Papers >
  1. 1 and 2 only
  2. 2 and 3 only
  3. 3 and 4 only
  4. 1 and 4 only

Answer (Detailed Solution Below)

Option 4 : 1 and 4 only
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
20 Qs. 40 Marks 24 Mins

Detailed Solution

Download Solution PDF

Concept:

  • LTI system is causal when h[n] = 0 for n < 0
  • LTI system is stable when  i.e. It should be absolutely summable.


Calculation:

h[n] = u(n + 3) + u(n – 2) – 2 u(n – 7)

∵ h[n] ≠ 0     n < 0 ….. system is Non causal

 i.e. given impulse response is summable hence it is stable.

Latest UPSC IES Updates

Last updated on Jul 2, 2025

-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10. 

-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.

->  UPSC ESE admit card 2025 for the prelims exam has been released. 

-> The UPSC IES Prelims 2025 will be held on 8th June 2025.

-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.

-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.

Hot Links: teen patti circle teen patti master old version teen patti neta teen patti stars