The equation of the tangents to the ellipse 4x2 + 5y2 = 20 which are perpendicular to line 3x + 2y - 5 = 0 is

  1. 3y = 2x ± 
  2. 3y = 2x + 
  3. 3y = 2x + 
  4. 3y = 0

Answer (Detailed Solution Below)

Option 1 : 3y = 2x ± 
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UP TGT Hindi FT 1
125 Qs. 500 Marks 120 Mins

Detailed Solution

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Calculation:

The equation of the given ellipse is  4x2 + 5y2 = 20

It can be written as , which is comparable with the first standard form 

Here a2 = 5 and b2 = 4.

The given line is 3x + 2y - 5 = 0, its slope = -(3/2)

Since the tangents are perpendicular to the given line, the slope of the required tangents is 2/3 (from m1 m2 = -1)

Thus the equation of the required tangents is,

⇒ 

⇒ 

⇒ 

⇒ 

Additional Information Tangents to an Ellipse:

→ If the line y = mx + c touches the ellipse , then c2 = a2m2 + b2.

→ The straight lines  represent the tangents to the ellipse.

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