Question
Download Solution PDFThe difference in the water surface level of two reservoirs which are connected by a siphon is 8 m. The length of siphon is 600 m and its diameter 0.3 m. If the siphon is running full, then what is the discharge ? (Take f = 0.02)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Discharge can be calculated by the expression for head loss for pipes:
\(h_f=\frac{8Q^2}{\pi^2g}\times\frac{fL}{D^5}\)
where,
Q = discharge
f= friction factor
g = acceleration due to gravity
D = diameter of pipe
L = length of pipe
Calculation:Given
hf = 8 m
L = 600 m
D = 0.3 m
g = 9.81 m/s2
Head loss for pipe is
\(8=\frac{8Q^2}{\pi^2\times9.81}\times\frac{0.02\times600}{0.3^5}\)
\(Q=0.14m^3/s\)
Last updated on Jul 2, 2025
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