Question
Download Solution PDFThe center of the circle inscribed in the square formed by the lines x2 - 7x + 12 = 0 and y2 - 13y + 42 = 0 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The centre of the circle inscribed in a square is the same as the centre of the square.
Calculation:
The given lines forming the square are:
x2 - 7x + 12 = 0
⇒ (x - 4)(x - 3) = 0
⇒ x = 4 and x = 3
And, y2 - 13y + 42 = 0
⇒ (y - 7)(y - 6) = 0
⇒ y = 7 and y = 6
The co-ordinates of the centre will be the mid-point of sides: (3.5, 6.5).
Last updated on Jul 8, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.