Question
Download Solution PDFThe average height of 35 telecom towers which are arranged in an ascending order is 284 m. If the average height of first 17 telecom towers is 284 m and that of last 17 telecom towers is 286 m, then what is the height of 18th telecom tower? (In m)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Average of 35 towers = 284 m
Average of 1st 17 towers = 284 m
Average of last 17 towers = 286 m
Concept used:
\(Average = {Sum\; of \;observations \over Total \;number\; of\; observations}\)
Calculation:
Average of 1 to 17 = \({1\; to\; 17 \over 17} = 284\) ----- (1)
Average of 1 to 17 = 4828
Average of 18 to 34 = \({18\; to\; 34 \over 17} = 286\) ----- (2)
Average of 18 to 34 = 4862
From the given data, towers are arranged in ascending order
\(284 = {18\; to\; 34 \;+\; 1 \;to \;17 \;+ \;18th\over 35}\) ----- (3)
Substitute (1) and (2) in (3)
284 × 35 = 4862 + 4826 + 18th
9940 = 9690 + 18th
18th = 9940 - 9690
18th = 250
∴ The height of 18th telecom tower is 250m.
Last updated on Jun 12, 2025
-> OSSC CGL Final Merit List has been released on the official website.
->The merit list consist the names of the candidates found suitable after the CV round.
->Earlier,The OSSC CGL Call Letter had been released for the Document Verification (Advt No.1249/OSSC).
-> Interested candidates registered from 29th November 2024 to 28th December 2024.
-> The recruitment is also ongoing for 543 vacancies (Advt. No. 129/OSSC). The Prelims was held on 20th October 2024 and thee Mains Exam will be scheduled in February/ March 2025.
-> The selection process includes Prelims, Mains, Skill Test, and Document Verification.
-> To score well in the exam, you may enhance your preparation by solving the OSSC CGL Previous Years' Papers.
-> Candidates can also attend the OSSC CGL Test Series which helps to find the difficulty level.