The average gate power dissipation for an SCR is 0.5 W. Gate voltage variation is 2 V to 10 V. Which of the following is true?

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UKPSC JE Electrical 2013 Official Paper II (Held on 7 Nov 2015)
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  1. Vg = 2 V, Ig = 0.25 A;

    Vg = 10 V, Ig = 0.05 A

  2. Vg = 2 V, Ig = 0.05 A;

    Vg = 10 V, Ig = 0.25 A

  3. Vg = 2 V, Ig = 10 A ;

    Vg = 10 V, Ig = 2 A

  4. None of the above

Answer (Detailed Solution Below)

Option 1 :

Vg = 2 V, Ig = 0.25 A;

Vg = 10 V, Ig = 0.05 A

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UKPSC JE CE Full Test 1 (Paper I)
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Detailed Solution

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Solution: 

Given,

Average gate power dissipation = 0.5 W

i.e., Pg = Vg Ig = 0.5 W

Given Range of Gate voltage is 2 V to 10 V

Case (i)

Consider, Vg = 2 V

∴ 

Case (ii)

Consider, Vg = 10 V

 

Therefore, the correct option will be 1.

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