Question
Download Solution PDFరెండు సంఖ్యల మొత్తం 288 మరియు వాటి HCF 16. అటువంటి సంఖ్యల యొక్క ఎన్ని జతలను రూపొందించవచ్చు?
Answer (Detailed Solution Below)
Detailed Solution
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రెండు సంఖ్యల మొత్తం 288 మరియు వాటి HCF 16
లెక్కలు:
సంఖ్య నిష్పత్తి x : y గా ఉండనివ్వండి
కాబట్టి సంఖ్యలు 16x & 16y (HCF అనేది ఒక సంఖ్య యొక్క అంతర్భాగం)
ప్రశ్న ప్రకారం
16x + 16y = 288
⇒ 16(x + y) = 288
⇒ x + y = 18
x, y జతలు (1, 17) (5, 13) (7, 11) కావచ్చు
కాబట్టి 3 జతల మాత్రమే ఉండవచ్చు.
∴ సరైన ఎంపిక ఎంపిక 1.
Last updated on Jun 30, 2025
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