Question
Download Solution PDFసిరీస్ మొత్తాన్ని కనుగొనండి : (20 + 22 + 24 +........+28) × 3
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన:
(20 + 22 + 24 +........+28) × 3
వాడిన ఫార్ములా:
ఇది ఒక రేఖాగణిత పురోగతి.
a = మొదటి పదం, r = సాధారణ నిష్పత్తి
జ్యామితీయ పురోగమనం మొత్తం = [a(r n - 1)/(r - 1)]
లెక్కింపు:
a = 1
r = (22/20) = 4/1 = 4
⇒ శ్రేణి మొత్తం = [1 × (45 - 1)/(4 - 1)] × 3
⇒ శ్రేణి మొత్తం = [1 × (210 - 1)/(3)] × 3
⇒ శ్రేణి మొత్తం = [1 × (1024 - 1)]
⇒ శ్రేణి మొత్తం = [1 × (1023)]
⇒ శ్రేణి మొత్తం = 1023
∴ సిరీస్ మొత్తం 1023.
ప్రత్యామ్నాయ పద్ధతి
(20 + 22 + 24 +........+28) × 3
⇒ (1 + 4 + 16 + 64 + 256) × 3
⇒ 341 × 3 = 1023
∴ సిరీస్ మొత్తం 1023.
Last updated on Jul 2, 2025
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