400 మరియు 600 మధ్య ఉన్న సంఖ్యల మొత్తాన్ని కనుక్కోండి, అవి 6, 12 మరియు 16తో భాగించబడినప్పుడు, శేషం ఉండదు?

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NTPC CBT-I (Held On: 8 Jan 2021 Shift 2)
View all RRB NTPC Papers >
  1. 2620
  2. 2016
  3. 2026
  4. 2610

Answer (Detailed Solution Below)

Option 2 : 2016
Free
RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
100 Qs. 100 Marks 90 Mins

Detailed Solution

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ఇచ్చిన:

మనం 400 - 600 పరిధిలోని సంఖ్యల మొత్తాన్ని కనుగొనాలి, అవి ప్రతి 6, 12 మరియు 16 ద్వారా భాగించబడతాయి.

భావన:

క.సా.గు (కనిష్ట సామాన్య గుణిజం)

గణన:

క.సా.గు (6, 12, 16) = 48

అవసరమైన సంఖ్యలు 48k రూపంలో ఉంటాయి, ఇక్కడ k అనేది సహజ సంఖ్య.

k = 9 కోసం, 48k = 48 x 9 = 432

k = 10 కోసం, 48k = 48 x 10 = 480

k = 11 కోసం, 48k = 48 x 11 = 528

k = 12. 48k = 48 x 12 = 576

∴ ఈ 4 సంఖ్యల అంటే 432, 480, 528 మరియు 576 మొత్తం 2016.

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