Question
Download Solution PDFR, S and T can finish a work in 20, 15 and 10 days, respectively. R works on all days and S and T work on alternate days with T starting the work on the first day. In how many days is the work finished?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
R, S and T can finish a work in 20, 15 and 10 days, respectively
R works on all days and S and T work on alternate days with T starting the work on the first day.
Formula Used:
Efficiency = Total work/Time taken
Calculation:
Let the total work be 60 units(LCM of 20, 15, and 10).
Efficiency of R = 60/20 = 3 units/day
The efficiency of S = 60/15 = 4 units/day
Efficiency of T = 60/10 = 6 units/day
On the first day, R and T work = 9 units
On the second day, R and S work = 7 units
2 day's work → 16 units
6 day's work → 48 units
7 day's work → 57 units
The remaining work of 3 unit is done by R and S in = 3/7 days
Total Time = 7 + 3/7 = 52/7 days
∴ In 52/7 days the work was finished.
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