Question
Download Solution PDFसमभुज चौकोनाची परिमिती 120 मीटर आहे आणि कोणत्याही दोन समांतर बाजूंमधील अंतर 15 मीटर आहे. समभुज चौकोनाचे क्षेत्रफळ किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
समभुज चौकोनाची परिमिती = 120 मीटर
गणना:
समभुज चौकोनाच्या प्रत्येक बाजूची लांबी = 120/4 = 30 मीटर
समभुज चौकोनाची उंची = 15 मीटर
समभुज चौकोनाचे क्षेत्रफळ = लांबी x उंचीचा पाया
= 30 x 15
= 450 चौरस मीटर
∴ समभुज चौकोनाचे क्षेत्रफळ 450 चौरस मीटर आहे
Last updated on Jun 11, 2025
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