Question
Download Solution PDFजर एका वर्तुळाच्या केंद्रापासून 21 सेमी अंतरावर काढलेल्या जीवेची लांबी 40 सेमी असेल, तर वर्तुळाची त्रिज्या (सेमीमध्ये) काढा:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेले आहे:
जीवा = 40 सेमी
केंद्रापासून जीवेचे अंतर = 21 सेमी
संकल्पना:
जीवेच्या केंद्रापासून काढलेला लंब हा त्या जीवेला दोन समान भागांमध्ये विभाजित करतो.
पायथागोरसचे प्रमेय:
OA2 = OD2 + AD2
गणना:
समजा, AB ही 40 सेमी लांबीची जीवा आहे.
⇒ OD हे लंब अंतर आहे.
⇒ AO ही वर्तुळाची त्रिज्या आहे.
OA2 = OD2 + AD2
⇒ OA2 = 212 + (40/2)2
⇒ OA2 = 441 + 400
⇒ OA2= 841
OA = √841
OA = 29
वर्तुळाची त्रिज्या (सेमीमध्ये) 29 आहे.
Last updated on Jul 16, 2025
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