Question
Download Solution PDFLet L1 and L2 be two parallel lines with the equations \(\rm \vec{r}=\vec{a}_1 +\lambda \vec{b}\) and \(\rm r=\vec{a}_2 + \mu\vec{b}\) respectively. The shortest distance between them is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- If two lines are parallel, then the distance between them is fixed.
- The distance between two parallel lines \(\rm \vec{r}=\vec{a}_1 +\lambda \vec{b}\) and \(\rm r=\vec{a}_2 + \mu\vec{b}\) is given by the formula: \(\rm d=\left|\dfrac{\vec{b}\times (\vec{a}_2-\vec{a}_1)}{|\vec{b}|}\right|\).
Calculation:
Using the formula for the distance between two parallel lines, we can say that the distance is \(\rm d=\left|\dfrac{\vec{b}\times (\vec{a}_2-\vec{a}_1)}{|\vec{b}|}\right|\).
Last updated on Jul 4, 2025
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