Let f(x + y) = f(x) f(y) and f(2) = 4 for all x, y ϵ R, where f(x) is continuous function. What is f' (2) equal to?

  1. 2 ln 2
  2. 4 ln 2
  3. ln 8
  4. 2 ln 3

Answer (Detailed Solution Below)

Option 2 : 4 ln 2
Free
NDA 01/2025: English Subject Test
5.6 K Users
30 Questions 120 Marks 30 Mins

Detailed Solution

Download Solution PDF

Concept:

\({\rm{f}}\left( {\rm{x}} \right) = {{\rm{a}}^{\rm{x}}},{\rm{Then\;f'}}\left( {\rm{x}} \right) = {{\rm{a}}^{\rm{x}}}\ln {\rm{a}}\)

Calculation:

Given that:  

f(2) = 4 and f (x + y) = f(x) f(y)

Putting x = 1, y = 1

f(2) = f(1) f(1) = 4

f(1) = f(1) = 2

i.e., f(1) = 21

Putting, x = 1, and y = 2

f (3) = f(1) f(2) = 2 × 4 = 23

∴ f(x) = 2x

⇒ f’(x) = 2x ln 2

∴ f’(2) = 22 ln 2 = 4 ln 2

Hence, option (2) is correct.
Latest NDA Updates

Last updated on Jun 18, 2025

->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Get Free Access Now
Hot Links: online teen patti teen patti lotus teen patti master official