In the circuit of the ideal Op-Amp, V0 is

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  1. - 1 V
  2. 2 V
  3. +1 V
  4. +15 V

Answer (Detailed Solution Below)

Option 4 : +15 V
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Detailed Solution

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By redrawing the circuit, we get

As shown in the circuit diagram, given op-amp is inverted grounded and output is corresponding to the non-inverted terminal.

∴ V = +Vcc = 15 volt

Now by applying KCL at node ‘V’ we get

I1 = I2

1 – V = V – V0

V= 2V - 1 

V= 29 volt

But output voltage can't be greater than higher saturation voltage (Vcc)

∴ Output voltage (V0) = +15 volt

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