Question
Download Solution PDFIn group II B, which metal has greater tendency to form coordination compound?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Group IIB Elements and Their Coordination Behavior
- Group IIB includes Zinc (Zn), Cadmium (Cd), and Mercury (Hg).
- While all form +2 oxidation state, their tendency to form coordination compounds varies due to:
- Atomic size and polarizability
- Softness or hardness of the metal ion
- Type of ligand (hard vs soft)
- Hg²⁺ is a soft Lewis acid and forms very stable complexes with soft ligands like CN⁻, S²⁻, and phosphines.
- This high affinity for soft ligands makes mercury form more stable and varied coordination compounds than Zn or Cd.
EXPLANATION:
- Zinc and cadmium, on the other hand, have smaller atomic radii and do not exhibit such a pronounced tendency to form coordination compounds as mercury does.
- Zn²⁺ and Cd²⁺ are hard acids → form weaker complexes with soft ligands.
- Hg²⁺ being larger and more polarizable (soft acid) → forms strong coordination complexes especially with soft ligands.
- Examples: [Hg(CN)₄]²⁻, [Hg(SCN)₄]²⁻
Therefore, among group IIB elements, mercury (Hg) has the greatest tendency to form coordination compounds, especially with soft ligands.
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