In an air-conditioning plant, air enters the cooling coil at 27°C. The coil surface temperature is -5°C. If the bypass factor of the unit is 0.4, the air will leave the coil at:

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ESE Mechanical 2016 Paper 1: Official Paper

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Answer 1

Concept:

Bypass Factor represents the fractional part of total inlet air which is not in contact with the coil.

Bypass factor of a cooling coil is given by

\(BPF = \frac{{{T_{outlet}} - {T_{coil}}}}{{{T_{inlet}} - {T_{coil}}}}\)

Calculation:

F2 M.J Madhu 15.04.20 D7

Given, BPF = 0.4, T₁ = 27°C, T_c = -5°C,

\(0.4 = \frac{{{T_2} - \left( { - 5} \right)}}{{27 - \left( { - 5} \right)}}\)

T₂ + 5 = 12.8°C

⇒ T₂ = 7.8°C