If the sum of the zeros of the polynomial (kx² - 3x - 6k) is equal to their product, then the value of k is -

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Question

This question was previously asked in

Rajasthan 3rd Grade (Maths & Science) Official Paper (Held On: 25 Feb 2023 Shift 2)

Answer 1

Given:

Polynomial: kx² - 3x - 6k

Sum of zeros = Product of zeros

Formula Used:

Sum of zeros = -b/a

Product of zeros = c/a

Calculation:

For the polynomial kx² - 3x - 6k:

a = k, b = -3, c = -6k

Sum of zeros = -b/a = -(-3)/k = 3/k

Product of zeros = c/a = -6k/k = -6

Given that Sum of zeros = Product of zeros:

⇒ 3/k = -6

⇒ k = 3/(-6)

⇒ k = -1/2

The value of k is -1/2.

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