If log2 = 0.3010 and log 3 = 0.4771, then the value of log 6 is

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HP JBT TET 2013 Official Paper
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  1. 0.8177
  2. 0.7781
  3. 0.6781
  4. 0.7681

Answer (Detailed Solution Below)

Option 2 : 0.7781
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HP JBT TET 2021 Official Paper
150 Qs. 150 Marks 150 Mins

Detailed Solution

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Given:
log 2 = 0.3010

log 3 = 0.4771

Formula used:

log (x × y) = log x + log y

Calculation:

log 6 = log (2.3)

⇒ log (2.3) = log 2 + log 3

⇒ log (2.3) = 0.3010 + 0.4771 = 0.7781

∴ log 6 = 0.7781.

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