If centre of the circle lies on the intersection of lines x + y = 1 and y = 2 and also cuts the circle x2 + y2 = 9 orthogonally then find the equation of the circle.

  1. x2 + y2 + 2x - 4y - 9 = 0
  2. x2 + y2 - 2x + 4y - 9 = 0
  3. x2 + y2 + 4x - 2y - 9 = 0
  4. Doesn’t exist

Answer (Detailed Solution Below)

Option 4 : Doesn’t exist
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

Concept:

  • Condition of orthogonality = 2g1g2 + 2f1f2 = c1 + c2


Calculation:

Centre lies on intersection of lines x + y = 1 and y = 2,

So point of intersection = (-1, 2) = (-g, -f)

So g = 1, f = -2

Given circle = x2 + y2 - 9 = 0

Lets equation of that orthogonal circle is x2 + y2 + 2gx + 2fy + c = 0

Checking for the condition 2g1g2 + 2f1f2 = c1 + c2

⇒ 2. g. (0) + 2. f. (0) = c - 9

⇒ c = 9

So g = 1, f = -2 and c = 9

Radius of circle =  = 

This will be an imaginary number, so circle can’t be made.

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

More Circles Questions

Hot Links: dhani teen patti teen patti noble teen patti master game