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निर्देश: आगे आने वाले दो (02) प्रश्नांशों के लिए निम्नलिखित पर विचार कीजिए।
एक समांतर चतुर्भुज ABCD के तीन क्रमागत शीर्षों के निर्देशांक A(1, 3), B(-1, 2) और C(3, 5) हैं।
विकर्ण BD का समीकरण क्या है?
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BD का मध्य बिंदु AC के मध्य बिंदु के समान है
AC का मध्य बिंदु =
BD का समीकरण
y - 2 =
⇒ y - 2 =
⇒ 3y - 6 = 2x + 2
⇒ 2x - 3y + 2 + 6 = 0
⇒ 2x - 3y + 8 = 0
∴ विकर्ण BD का समीकरण 2x - 3y + 8 = 0 है
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