Question
Download Solution PDFThe area of the triangle formed by joining the centres of the circles
x2 + y2 + 2x + 4y - 4 = 0,
x2 + y2 + 6x + 4y + 9 = 0,
and x2 + y2 - 4x - 4y + 2 = 0 is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवृत्त के लिए सामान्य समीकरण
उस वृत्त की त्रिज्या =
केंद्र =
त्रिभुज का क्षेत्रफल:
शीर्ष
गणना:
Given the equation of circle are
x2 + y2 + 2x + 4y - 4 = 0 ----(1)
x2 + y2 + 6x + 4y + 9 = 0 -----(2)
x2 + y2 - 4x - 4y + 2 = 0 ----(3)
We know that, center of circle
are
Hence, the center of given circles are
A(-1, -2), B(-3, -2), C(2, 2)
Hence, the area of a triangle ABC is
Δ =
Δ =
⇒ Δ = 4 sq. unit
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