यदि y = me+ ne-x है, तो दिए गए फलन के लिए कौन-सा संबंध सही है?

Answer (Detailed Solution Below)

Option 4 :
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
150 Qs. 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

कुछ उपयोगी सूत्र निम्न हैं:

गणना:

दिया गया फलन निम्न है, 

y = me+ ne-x

फलन का अवकलन करने पर हमें निम्न प्राप्त होता है, 

आगे x के संबंध में अवकलन करने पर, हमें निम्न प्राप्त होता है 

आगे x के संबंध में अवकलन करने पर, हमें निम्न प्राप्त होता है

 

अब, 

= 0

अतः 

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Hot Links: teen patti app teen patti - 3patti cards game teen patti gold new version teen patti classic