Question
Download Solution PDFयदि f (x) = 3 1 + x है, तब f (x) f (y) f (z) किसके बराबर है
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना :
दिया गया: f (x) = 3 1+ x
फिर,
⇒ f (y) = 3 1+ y
⇒ f (z) = 3 1+ z
हमें f (x) f (y) f (z) का मान ज्ञात करना होगा,
⇒ f (x) f (y) f (z) = 3 1+ x × 3 1+ y × 3 1+ z
⇒ f (x) f (y) f (z) = 3 3+ x + y + z = 3 1 + 2 + x + y + z = f (x + y + z + 2)Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.