प्रायिकता घनत्व फलन f(x) = 4x3; 0 < x < 1 वाले यादृच्छिक चर X के लिए, अन्तःचतुर्थक श्रेणी है:

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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SSC CGL Tier 1 2025 Full Test - 01
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दिया गया है

F(x) = 4x3

सूत्र

अन्तःचतुर्थक श्रेणी के लिए = Q3 – Q1

Q3 = 75/100

Q1 = 25/100

गणना

4x3dx = 75/100

⇒ ¾ = 4 (X4/4)Q30

⇒ ¾ = (Q43 – 0))

⇒ ¾ = Q43

∴ Q3 = (3/4)1/4

चतुर्थांश (Q1) के लिए,

25/100 = 4x3dx

⇒ ¼ = 4(x4/4)Q10

⇒ ¼ = (Q14 – 0)  

⇒ ¼ = Q14

∴ Q1 = (1/4)1/4

∴ अन्तःचतुर्थक श्रेणी Q3 – Q1 का मान (3/4)1/4  - (1/4)1/4 है।

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