यदि dy/dx = x3log(4x) है, तो Y(x) ज्ञात कीजिये।

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Airforce Group X MBT 18-Jul-2021 Shift 1
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  1. log(4x)x3/3 + x4/4
  2. log(4x)x4/4 + x4/16
  3. log(4x)x3/3 - x4/4
  4. log(4x)x4/4 - x4/16

Answer (Detailed Solution Below)

Option 4 : log(4x)x4/4 - x4/16
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Detailed Solution

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dy/dx = x3log(4x)

Y(x) =

Y(x) = ∫x3log(4x)dx

\(Y\left( x \right) = \log \left( {4x} \right)\frac{{{x^4}}}{4} - \smallint \frac{1}{{4x}}.4.\frac{{{x^4}}}{4}dx = \log \left( {4x} \right)\frac{{{x^4}}}{4} - \frac{1}{4}\smallint {x^3}dx = \log \left( {4x} \right)\frac{{{x^4}}}{4} - \frac{{{x^4}}}{{16}}\)

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