Question
Download Solution PDFComprehension
Direction: The given line graph shows the number of passengers travelled by 2 cab drivers and the table shows the percentage of females who travelled in the cabs in different months.
|
Month |
Driver A |
Driver B |
|
Percentage of Females |
Percentage of Females |
|
|
May |
30% |
50% |
|
June |
50% |
70% |
|
July |
20% |
40% |
|
August |
60% |
30% |
|
September |
40% |
50% |
Find the ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFemales in the month June = 250 × 50/100 = 125
Females in the month July = 200 × 20/100 = 40
The average of the female in the month of June and July by Driver A = (125 + 40)/2 = 82.5
Percentage of males in the month June = 100 - 70 = 30
Males in the month June = 350 × 30/100 = 105
Percentage of males in the month of July = 100 - 40 = 60
Males in the month July = 250 × 60/100 = 150
The average of the Males in the month of June and July by Driver B = (105 + 150)/2 = 127.5
The ratio of the average of the female in the month of June and July by Driver A to the average of the males in the same month by Driver B
= 82.5 : 127.5 = 11 : 17
Last updated on Jul 3, 2025
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