Find the current 'i' in the given circuit.

The correct answer is option 3):(32 mA)

Concept:

When two resistors R₁ and R₂ are connected in series the total resistance 

R_t = R1 +R2

When two resistors R1 and R2 are connected in parallel the total resistance will be

R_t = ( + )^-1

Current Division method

Current through R₁ 

Current through R₂ 

By  ohms law 

V = IR 

where I is the current R is the resistor

Calculation:

Given

The circuit  can be simplified as

R₁ = 500 Ω 

R₂ = 150 Ω + 600 Ω = 750 Ω 

Total resistance = (  + )^-1+ 200

= 500 Ω 

I = 

= 0.08 A

 = i

= 0.08 × 

= 0.032 A

= 32mA