ত্রিকোণমিতিক সূত্র ব্যবহার করে, \(\rm \left(\frac{\sin (x-y)}{\sin(x+y)}\right)\rm \left(\frac{\tan x+\tan y}{\tan x-\tan y}\right)\)এর মান নির্ণয় করুন।

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SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 1)
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  1. -2
  2. 2
  3. 0
  4. 1

Answer (Detailed Solution Below)

Option 4 : 1
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Detailed Solution

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অনুসৃত সূত্র:

Sin (A - B) = sin A × cos B - cos A × sin B

Sin (A + B) = sin A × cos B + cos A × sin B

গণনা:

\(\rm \left(\frac{\sin (x-y)}{\sin(x+y)}\right)\rm \left(\frac{\tan x+\tan y}{\tan x-\tan y}\right)\)

⇒ (sin x × cos y - cos x × sin y)/(sin x × cos y + cos x × sin y) × {(sin x/cos x) + (sin y/cos y)}/{(sin x/cos x) + (sin y/cos y)}

⇒ (sin x × cos y - cos x × sin y)/(sin x × cos y + cos x × sin y) × {(sin x × cos y) + (sin y × cos x/(cos x) × (cos y)}/{(sinx × cos y) + (sin y × cos x)/(cos x) × (cosy)}

⇒ (sin x × cos y - cos x × sin y)/(sin x × cos y + cos x × sin y) × (sin x × cos y) + (siny × cos x)/(sin x × cos y) + (sin y × cos x)

⇒ 1

∴ সঠিক উত্তর হল 1

Alternate Methodগণনা:

যদি আমরা x = 45°, এবং y = 0° রাখি তাহলে,

\(\rm \left(\frac{\sin (x-y)}{\sin(x+y)}\right)\rm \left(\frac{\tan x+\tan y}{\tan x-\tan y}\right)\) 

⇒ sin (45 - 0)/sin(45 + 0) × {(tan 45 + tan 0)/(tan 45 - tan 0)}

⇒ sin 45/sin 45 × {(1 + 0)/(1 - 0)} 

⇒ 1

∴ সঠিক উত্তর 1 হবে। 

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