Based on the data in table, answer the five questions that follow:

The following table shows the break‐up of population in terms of males, females and transgenders of five different cities A ‐ E. Some of the data in the table is in percent (%) while some data is in numbers.

City‐wise Break‐up of Population

City	Population Break-up
	Males	Females	Transgenders
A	45%	30%	2000
B	50%	3000	35%
C	8000	35%	15%
D	45%	3600	25%
E	38%	32%	4200

Female population in City 'C' is how much percent less than the sum of male and transgender population of City 'D'?

Concept Used:-

The percentage is a way of comparing the quantities. Suppose, 20 number is x% of y. Then, the relation between x and y can be given as,

\(\dfrac{x}{100}\times y=20\)

The percentage is the number or ratio which can be expression in the fraction of hundred.

For example, if we have to find out the x% of 50. Then, we have to divide x with 100 and multiplied with 50.

\(x\% \text{ of }50=\dfrac{x}{100}\times50\)69
Explanation:-

Total female population is city C \(=\frac{8000}{0.5} \times 0.35=5600\)
The sum of Male and transgender population in the city D,

\(\Rightarrow \frac{3600}{0.3} \times[0.7]=8400\)

Suppose, female population in City 'C' is x% less than the sum of male and transgender population of City 'D'. Thus,

\(\Rightarrow x=\frac{8400-5600}{8400} \times 100\\ \Rightarrow x=\frac{2800}{84} \%\\ \Rightarrow x =\frac{100}{3} \%\\ \Rightarrow x=33 \frac{1}{3} \%\)

So, the Female population in City 'C' is 33\(\frac{1}{3}\%\) less than the sum of male and transgender population of City 'D'.
Hence, the correct option is 2.