Question
Download Solution PDFAn isolated ‘T’ beam is used on walkway. The beam is simply supported with an effective span of 6m. Effective width of flange for shown figure is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Effective Width of Flange of the different section:
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Effective Width of Flange |
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Monolithic Beams |
T - Beams |
\({b_f} = {b_w} + \frac{{{l_o}}}{6} + 6{d_f}\) |
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L - Beams |
\({b_f} = {b_w} + 0.5\left( {\frac{{{l_o}}}{6} + 6{d_f}} \right)\) |
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Isolated Beams |
T - Beams |
\({b_f} = {b_w} + \frac{{{l_o}}}{{\frac{{{l_o}}}{b} + 4}}\) |
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L - Beams |
\({b_f} = {b_w} + \frac{{0.5 \times {l_o}}}{{\frac{{{l_o}}}{b} + 4}}\) |
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Where,
bf = Effective width of flange
lo = Distance between points of zero moments in the beam
bw = Breadth of the web
df = Thickness of the flange
b = Actual width of the flange
Explanation:
Given,
lo = 6m = 6000mm, b = 1000mm, bw = 300mm,
Walkway is the case of isolated T-Beam. Then,
\({b_f} = {b_w} + \frac{{{l_o}}}{{\frac{{{l_o}}}{b} + 4}}\)
\({{\bf{b}}_{\bf{f}}} = 300 + \frac{{6000}}{{\frac{{6000}}{{1000}} + 4}}\)
bf = 300 + 600 = 900mm
Last updated on Mar 26, 2025
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