A three-hinged parabolic arch subjected to a load w at L/4 distance from left support. The rise of the crown is 4 m, span is 20 m and w is 80 kN, the horizontal thrust at the support is

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  1. 40 kN
  2. 25 kN
  3. 50 kN
  4. 80 kN

Answer (Detailed Solution Below)

Option 3 : 50 kN

Detailed Solution

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For the given condition:

From equilibrium equation:

∑V = 0,

Taking moment about point A,

VB × 20 – 80 × 5 = 0

Hence, VA = 60 kN and VB = 20 kN

Taking MC = 0 from left portion(AC),

VA × 10 - 80 × 5 – H × 4 = 0

∴ H = 50 kN

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