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 A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many sums did he solve correctly?

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CSIR CERI JSA Official Paper-I (Held On: 2022)
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  1. 12
  2. 16
  3. 18
  4. 24

Answer (Detailed Solution Below)

Option 2 : 16
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Detailed Solution

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Given:

Total sums attempted = 48

A student got twice as many sums wrong as he got right.

Calculation:

Let the number of sums solved correctly be x.

Number of sums solved wrong = 2x

Total sums attempted = x + 2x = 48

⇒ x + 2x = 48

⇒ 3x = 48

⇒ x = 48 / 3

⇒ x = 16

The number of sums solved correctly is 16.

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