Question
Download Solution PDFA simply supported beam AB of length L is subjected to a uniformly distributed load w (force per unit length) over its entire span. What is the magnitude of the shear force at a section located at a distance \(\frac{L}{4}\) from the left support?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For a simply supported beam of length \( L \) subjected to a uniformly distributed load \( w \), the support reactions are:
\( R_A = R_B = \frac{wL}{2} \)
Shear Force at \( x = L/4 \):
\( V_{x=L/4} = R_A - \text{UDL Load up to } x \)
\( V_{x=L/4} = \frac{wL}{2} - \frac{wL}{4} \)
\( V_{x=L/4} = \frac{wL}{4} \)
Last updated on Jul 9, 2025
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